Q8 of 158 Page 159

In Fig. 6.8, PB = PD. The value of x is

Exterior angle of triangle is equal to sum of 2 opposite onterior angles.

As BC is straight line

∠PBD + 120° = 180°

∠PBD = 180° - 120°

∠PBD = 60°

As ΔPBD is isosceles triangle and PB = PD

∴ ∠PBD = ∠PDB

⇒ ∠PDB = 60°

In ΔPSR

With exterior angle ∠PSQ equal to sum of opposite inetrior angles

∠PDB = ∠DPC + ∠PCD

60° = x + 35°

x = 60° - 35°

x = 25°

In a triangle, one angle is of 90°. Then

(i) The other two angles are of 45° each

(ii) In remaining two angles, one angle is 90° and other is 45°

(iii) Remaining two angles are complementary

In the given option(s) which is true?

Lengths of sides of a triangle are 3 cm, 4 cm and 5 cm. The triangle is

In ∆PQR,

In ∆ABC,