Find the value of x in Fig. 6.38.

Formula Used/Theory:-
→ Exterior angle is equal to sum of interior opposite angles
In Δ ABC
When BC extended to D
Exterior angle ACD = ∠CAB + ∠ABC
∠ACD = 80° + 30° = 110°
∠ACD = ∠ACE + ∠ECD (As given in figure)
∠ACD = x + 90°
⇒ 110° = x + 90°
x = 110° - 90°
= 20°
Result:- The value of x comes out to be 20°
Couldn't generate an explanation.
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