Q17 of 158 Page 159

In ∆PQR, if PQ = QR and ∠Q = 100°, then ∠R is equal to

In ∆PQR


if PQ = QR


Then PQR is a isosceles triangle


Having, ∠P = ∠R


∠Q = 100°


As sum of all angles of triangle is 180°


Then;


∠P + ∠R + ∠Q = 180°


∠R + ∠R + 100° = 180°


2∠R = 80°


∠R = = 40°

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