ABC is an isosceles triangle with AB = AC and D is the mid-point of base BC (Fig. 6.48).
A. State three pairs of equal parts in the triangles ABD and ACD.
B. Is ∆ABD ≅ ∆ACD. If so why?

Given: AB = AC; D is midpoint of BC
As D is midpoint of BC
BD = DC
In Δ ADB and Δ ADC
AB = AC (given)
BD = DC (D is midpoint of BC)
AD = AD (common)
⇒ these are all 3 equal parts of triangles ABD and ACD
⇒ yes ∆ABD ≅ ∆ACD
Because it follows SSS congruence criterion
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