In Fig. 6.52, DE = IH, EG = FI and ∠E = ∠I. Is ∆DEF ≅ ∆HIG? If yes, by which congruence criterion?

Given: DE = IH, EG = FI and ∠E = ∠I
Formula Used/Theory:-
→ when 2 sides and angle between both the sides are equal in both the triangles then triangles are congruent by SAS congruence criterion
In Δ DEF and Δ GIH
⇒ DE = HI (Given)
EG = FI
If we add length of GF both sides
EG + GF = FI + GF
⇒ EF = IG
⇒ ∠E = ∠I
∴ ∆DEF ≅ ∆HIG
Hence; Both triangles are congruent by SAS criterion
Couldn't generate an explanation.
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