Q43 of 158 Page 159

In Fig. 6.18, M is the mid-point of both AC and BD. Then

In Δ ABM and Δ DCM


AM = MC ∵ M is midpoint of AC


DM = BM ∵ M is midpoint of BD


∠AMB = ∠DMC ∵ Vertically opposite angles


AMB ↔ CMD


Hence, Δ ABM ≅ Δ DCM


By congruency criteria AMB ↔ CMD


∠1 = ∠4;and ∠2 = ∠3

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