In Fig. 6.44, if RP = RQ, find the value of x.

Given:
Formula Used/Theory:-
If 2 sides are equal then triangle is Isosceles triangle
In isosceles triangle base angles of triangles are also equal
In Δ PQR
As QR = PR
Then;
∠PQR = ∠QPR
∠QPR = 50° (By vertical opposite angle)
∠PQR = x = 50°
Result:- the value of x comes out to be 50°
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