Q5 of 99 Page 264

The area of rectangular land of suhas’s is 500 sq. meter. If length of land is decreased by 3 meter and breadth is increased by 2 meter, then the land formed a square. Let us write by calculating the length and breadth of land of Suhas’s.

Let original length be L and original breadth be B.

L × B = 500.


Since length decreased by 3m and Breadth increased by 2m gives rise to a square,


L - 3 = B + 2 (Because in a square, L = B)


Or L = B + 5


(B + 5) × B = 500


B2 + 5B - 500 = 0


On solving the quadratic equation, we have B = 20 or B = - 25


Since the measurement cannot be negative,


B = 20


So L = B + 5 = 25


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