The area of rectangular land of suhas’s is 500 sq. meter. If length of land is decreased by 3 meter and breadth is increased by 2 meter, then the land formed a square. Let us write by calculating the length and breadth of land of Suhas’s.
Let original length be L and original breadth be B.
L × B = 500.
Since length decreased by 3m and Breadth increased by 2m gives rise to a square,
L - 3 = B + 2 (Because in a square, L = B)
Or L = B + 5
(B + 5) × B = 500
B2 + 5B - 500 = 0
On solving the quadratic equation, we have B = 20 or B = - 25
Since the measurement cannot be negative,
B = 20
So L = B + 5 = 25
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