If length of base of any isosceles triangles is 12 cm and length of each equal side is 10 cm. Let us write by calculating the area of that isosceles triangle.
Given, length of base of isosceles triangle (b) = 12cm
Length of equal side (a) = 10cm
Area of isosceles triangle = ![]()
= ![]()
=6 √64
= 6 × 8
= 48cm2
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