Q12 of 99 Page 269

Sahin draws a trapezium ABCD of which length of diagonal BD is 11 cm, and draws two perpendicular of which length are 5 cm and 11 cm respectively from the points A and C on the diagonal BD. Let us write by calculating the area of ABCD in the shape of trapezium.

Given, a trapezium ABCD of which length of diagonal BD is 11 cm

And two perpendicular of which length are 5 cm and 11 cm respectively from the points A and C on the diagonal BD.



According to the figure the area of the trapezium = area of ∆ABD + area ∆BCD


= ×BD×AM + ×BD×CN


= ×11×5 + ×11×11


= 27.5 + 60.5


= 88 sq. cm.


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