Q17 of 99 Page 269

The height of parallelogram is of its base. If the area of field is 192 sq.cm. in the shape of parallelogram the height is

Formula used:


area of parallelogram = base × height


⟹ 192 = base ×base


⟹ 192 = b2


⟹ b2 = 192×3


⟹ b2 = 576


⟹ b = 24cm


then height = base


= ×24


= 8cm

More from this chapter

All 99 →
15

In a trapezium, the length of each slant sides is 10 cm. and the length of parallel sides are 5 cm. and 17 cm. respectively. Let us write by calculating area of filed in shape of trapezium and its diagonal.

 16

The lengths of parallel sides of a trapezium are 19 cm. and 9 cm. and the length of slant sides are 8 cm. and 6 cm. Let us calculate the area of the field in the shape of trapezium.

 17

If the length of one side of a rhombus is 6 cm. and one angle is 60°, then area of field in the shape of rhombus is

 17

The length of one diagonal of rhombus is three times of another diagonal. If the area of field in the shape of rhombus is 96 cm2, then the length of long diagonal is