Q4 of 99 Page 269

Pritha draws a parallelogram of which adjacent sides are 25 cm and 15 cm and length of one diagonal is 20 cm. Let us write by calculating the height of parallelogram which is drawn on the side of 25 cm.


Given, a parallelogram of which adjacent sides are 25 cm and 15 cm and length of one diagonal is 20 cm.


Consider a parallelogram ABCD, adjacent sides are given, AB=25cm


BC=15cm


And diagonal AC=20cm


Semi perimeter of ∆ABC, S =


S = 30cm


Hence area of ∆ABC = sq. cm


Area ∆ABC = 150 sq. cm


Area of parallelogram ABCD = 2×area of ∆ABC


Area of parallelogram ABCD = 2×150


= 300sq. cm


Let, Height AE = h


Area of parallelogram ABCD= base × height


⟹ 300 = 25 × h


⟹ h =


⟹ h = 12cm


More from this chapter

All 99 →
2

The base of a parallelogram is twice its height. If the area of shape of parallelogram is 98 sq.cm, then let us calculate the length and height of parallelogram.

 3

There is a shape of parallelogram land beside our house of which lengths of adjacent sides are 15 meter and 13 meter. If the length of one diagonal is 14 meter, then let us calculate the area of shape of parallelogram land.

 5

The length of adjacent two sides are 15 cm. and 12 cm. of a parallelogram distance between two smaller sides is 7.5 cm. Then let us calculate the distance between the longer two sides.

 6

If the measure of two diagonals of a rhombus are 15 meter and 20 meter, then let us write by calculating its perimeter, area and height.