Q10 of 99 Page 269

Let us write by calculating the area of regular hexagon field of which length of sides is 8 cm. [Hints: If we draw diagonals we get equal six equilateral triangles]

Given, a regular hexagon field of which length of sides is 8 cm

We know that the regular hexagon consists of six equilateral triangles.


Hence,


Area of hexagonal field = 6 × area of a equilateral triangle.


Area of hexagonal field = 6 ×a2


= 6××82


= 166.3 sq. cm.


More from this chapter

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8

If perimeter of a rhombus is 20 cm. and length of its one diagonal is 6 cm, then let us write by calculating the area of rhombus.

 9

The area of field shaped in trapezium is 1400 sq. dcm. If the perpendicular distance between two parallel sides are 20 dcm and the length of two parallel sides are in the ratio 3 : 4, then let us write by calculating the lengths of two sides.

 11

In a quadrilateral ABCD, AB = 5 meter, BC = 12 meter, CD = 14 meter, DA = 15 meter and ∠ABC = 90°, let us write by calculating the area of quadrilateral shape of field.

 12

Sahin draws a trapezium ABCD of which length of diagonal BD is 11 cm, and draws two perpendicular of which length are 5 cm and 11 cm respectively from the points A and C on the diagonal BD. Let us write by calculating the area of ABCD in the shape of trapezium.