Q4 of 99 Page 267

If each equal side of an isosceles triangle ABC is 10 cm. and length of base is 4 cm. Let us write by calculating the area of ΔABC.

Given, equal side of isosceles triangle (a)= 10cm


Length of base (b) = 4cm


Area of isosceles triangle =


where ‘b’ is base and ‘a’ is length of two equal sides


=


= 2√96 cm2


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