Any adjacent parallel sides of a trapezium makes an angle 45° and length of its slant side in 62 cm., what is the distance between two parallel sides.
Let us consider a trapezium ABCD, such that AB || CD and BC be the slant height such that BC = 62 cm, and ∠ABC = 45°
To find: Distance between two parallel lines i.e. CP.

In ΔACP
We know,
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⇒ CP = 31√2 cm
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