Q20 of 99 Page 264

If the length of square is increased by 10%, then what percent of the area of square will be increased?

Let original Length be L.

10% increase is 0.1L


New Length = L + 0.1L = 1.1L.


Change in area = (1.1L)2 –L2 = 0.21L2


%change in area =


= 21%


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