Q7 of 99 Page 269

If perimeter of a rhombus is 440 meter and distance between two parallel sides are 22 meter, let us write by calculating the area of shape of rhombus.

Given, perimeter of a rhombus is 440 meter and distance between two parallel sides are 22meter.

Perimeter of Rhombus = 4×side of square(a)


Hence, 440 = 4a


⟹ a =


⟹ side, a = 11m


Area of rhombus = side of square (a)× height (distance between two parallel sides)


Hence, Area of rhombus = 11 × 22


= 242 sq. m


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