Q21 of 99 Page 267

D is such a point on AC of triangle ABC so that AD : DC = 3 : 2. If the area of triangle ABC is 40 sq.cm., the area of triangle BDC is

Given



⇒ 2AD = 3DC


But AC = AD +CD


⇒


⇒


Area of triangle ABC = 40 cm2 (given)


But



⇒ DC × BD = 32 ………eq 1


Also Area of triangle BDC =


Area of triangle BDC =


= 16 cm2


Hence the solution is option A

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