Given Differential equation is :
⇒
……(1)
Homogeneous equation: A equation is said to be homogeneous if f(zx,zy) = znf(x,y) (where n is the order of the homogeneous equation).
Let us assume:
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⇒ ![]()
⇒ ![]()
⇒ ![]()
⇒ f(zx,zy) = z0f(x,y)
So, given differential equation is a homogeneous differential equation.
We need a substitution to solve this type of linear equation, and the substitution is y = vx.
Let us substitute this in (1)
⇒ ![]()
We know that:
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⇒ ![]()
⇒ ![]()
⇒ ![]()
⇒ ![]()
⇒ ![]()
Bringing like variables on one side we get,
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⇒ ![]()
⇒ ![]()
⇒ ![]()
We know that:
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and Also,
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Integrating on both sides, we get,
⇒ ![]()
⇒ ![]()
(∵ LogC is an arbitrary constant)
⇒ ![]()
(∵
)
Since y = vx,
we get ![]()
⇒ ![]()
(∵ xloga = logax)
⇒ ![]()
⇒ ![]()
⇒ ![]()
⇒ ![]()
(Assuming log(c2) = K a constant)
∴ The solution to the given differential equation is log(y2 + x2) + 2tan-1
= K
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