Solve the following initial value problem:

Given differential equation

Find: Find the general solution of this differential equation.

=

=

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On Integrating we get,

= y – 2log|y + 2|=log |x| + log |C| ….(i)

Put y = 0, x = 2

= 0 – 2log2 = log 2 + log c

= -2 log 2 –log 2 = log C

= -3 log 2 = log c

= =log c

Put the value of C in equation (i)

Hence, y – 2log|y + 2|=