Solve the following equations:

Given differential equation is:
⇒
……(1)
Homogeneous equation: A equation is said to be homogeneous if f(zx,zy) = znf(x,y) (where n is the order of the homogeneous equation).
Let us assume:
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⇒ ![]()
⇒ ![]()
⇒ ![]()
⇒ f(zx,zy) = z0f(x,y)
So, given differential equation is a homogeneous differential equation.
We need a substitution to solve this type of linear equation and the substitution is y = vx.
Let us substitute this in (1)
⇒ ![]()
We know that:
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⇒ ![]()
⇒ ![]()
⇒ ![]()
⇒ ![]()
⇒ ![]()
Bringing like variables on same side we get,
⇒ ![]()
⇒ ![]()
⇒ ![]()
⇒ ![]()
We know that:
and
Also,
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Integrating on both sides, we get,
⇒ ![]()
⇒ ![]()
⇒ ![]()
Since y = vx, we get,
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⇒ ![]()
⇒ ![]()
⇒ ![]()
(∵
)
⇒ ![]()
⇒ ![]()
(∵ alogx = logxa)
⇒ ![]()
⇒ ![]()
∴ The solution for the given Differential equation is ![]()
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