Solve the following differential equations :
xdy = (2y + 2x4 + x2)dx
(i) If a differential equation is
,
then y(I.F) = ∫Q.(I.F)dx + c, where I.F = e∫Pdx
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Given:-
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This is a linear differential equation, comparing it with
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,
Q = 2x3 + x
I.F = e∫Pdx
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= e–2logx
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= ![]()
Solution of the equation is given by
y(I.F) = ∫Q.(I.F)dx + c
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