Solve the following differential equations :

(i) If a differential equation is
,
then y(I.F) = ∫Q.(I.F)dx + c, where I.F = e∫Pdx
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Given:-

This is a linear differential equation, comparing it with
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I.F = e∫Pdx
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Solution of the equation is given by
y(I.F) = ∫Q.(I.F)dx + c

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so,
yt = ∫t.dt + c
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