Find the equation of the curve which passes through the point (3, – 4) and has the slope
at any point (x, y) on it.
Given the slope of the tangent = ![]()
We know that slope of tangent = ![]()
∴ ![]()
⇒ ![]()
Integrating both sides,
⇒ ![]()
⇒ ![]()
⇒
……(1)
Now, the curve passes through (3, – 4)
So, it must satisfy the above equation
∴ ![]()
⇒ – 4 = (3)2× c
⇒ – 4 = 9c
⇒ c = ![]()
Putting the value of c in equation (1)
∴ ![]()
Couldn't generate an explanation.
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