Solve the following differential equations :

(i) If a differential equation is
,
then y(I.F) = ∫Q.(I.F)dx + c, where I.F = e∫Pdx
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Given:-
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This is a linear differential equation, comparing it with
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Q = log x
I.F = e∫Pdx
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= elog|x|
= x, x>0
The solution of the equation is given by
y(I.F) = ∫Q.(I.F)dx + c
⇒ yx = ∫logx.x.dx + c
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