Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients.
4x2 + 8x
To find the zeros of the polynomial let us first solve the polynomial by equating it to zero. Factorizing the given polynomial
4x2 + 8x = 0
4x(x + 8) = 0
4x = 0 or x + 8 = 0
Now solving the first part,
4x = 0
x = 0/4
x = 0
Now solving the second part,
x + 8 = 0
x = -8
When we compare the above quadratic equation with the generalized one we get,
ax2 + bx + c = 0
∴ a = 4, b = 8, c = 0
Sum of zeroes = -b / a
= -8 / 4
= -2
Product of zeroes = c / a
= 0 / 4
= 0
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