Q2 of 108 Page 38

Dividing the first polynomial, by the second polynomial, check whether the first polynomial is a factor of the second polynomial:

g(x) = x3 – 3x + 1, f(x) = x5 – 4x3 + x2 + 3x + 1


The solution is as follows:


Since the remainder is not zero, it is proved that the first polynomial is not the factor of second.


Remainder is 9x – 3


More from this chapter

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2

Dividing the first polynomial, by the second polynomial, check whether the first polynomial is a factor of the second polynomial:

g(x) = x2 + 3x + 1, f(x) = 3x4 + 5x3 – 7x2 + 2x + 2


 2

Dividing the first polynomial, by the second polynomial, check whether the first polynomial is a factor of the second polynomial:

g(t) = t2 – 3, f(t) = 2t4 + 3t3 – 2t2 – 9t – 12


 3

With the following polynomials their zeroes are given. Find their all other zeroes:


 3

With the following polynomials their zeroes are given. Find their all other zeroes: