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3. Polynomials
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Q2 of 108 Page 40

Solve the following equations by factorization method:


On factorizing the above equation,

3x2 – 2√6x + 2 = 0


3x2 - √6x -√6x + 2 = 0


√3x(√3x - √2) – √2(√3x - √2) = 0


(√3x - √2) (√3x - √2) = 0


Here both the roots are equal.


So √3x - √2 = 0


√3x = √2


x = √2 / √3


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Questions · 108
3. Polynomials
1 1 1 1 1 1 2 2 2 2 2 2 3 1 1 1 1 2 2 2 3 3 3 4 1 1 1 1 2 2 2 2 2 2 2 2 2 2 2 1 1 1 1 1 1 1 2 2 2 2 2 2 3 4 5 1 1 1 1 1 1 2 2 2 2 2 2 3 3 3 4 5 1 1 1 1 1 2 3 4 5 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 19 19 19 20 21 21 22 23
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