Find that value of k in the following quadratic equation whose roots are real and equal:
2x2 + kx + 3 = 0
When we compare the above quadratic equation with the generalized one we get,
ax2 + bx + c = 0
a = 2
b = k
c = 3
Since the quadratic equations have real and equal roots,
b2 – 4ac = 0 for real and equal roots
⟹ (k) 2 – (4 × 2 × 3) = 0
⟹ k2 – 24 = 0
⟹ k2 = 24
⟹ k = √( 2 × 2 × 6)
⟹ k = ± 2√6
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