Find the root of the following quadratic equations, if they exist, by using the quadratic formula by Shridharacharya Method:

Let us solve the above equation by equating it to zero,
![]()
![]()
![]()
-2 = 3(x2 – 2x)
3x2 – 6x + 2 = 0
When we compare the above quadratic equation with the generalized one we get,
ax2 + bx + c = 0
a = 3
b = -6
c = 2
There is one formula developed by Shridharacharya to determine the roots of a quadratic equation which is as follows:
![]()
Before putting the values in the formula let us check the nature of roots by b2 – 4ac >0
⟹ (-6)2 – (4 × 3 × 2)
⟹ 36 – 24
⟹ 12
Since b2 – 4ac = 5 the roots are real and distinct.
Now let us put the values in the above formula

![]()
![]()
![]()
![]()
![]()
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.