Solve the following quadratic equations by the method of completing the square:
2x2 + x – 4 = 0
Now in the above quadratic equation the coefficient of x2 is 2. Let us make it unity by dividing the entire quadratic equation by 2.
x2 + 1/2x - 2 = 0
x2 + 1/2 x = 2
Now by taking half of the coefficient of x and then squaring it and adding on both LHS and RHS sides.
Coefficient of x = 1/2
Half of 1/2 = 1/4
Squaring the half of 1/2 = 1/16
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Now the LHS term is a perfect square and can be expressed in the form of (a-b) 2 = a2 – 2ab + b2 where a = x and b = 1/4
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On simplifying both RHS and LHS we get an equation of following form,
(x ± A)2 = k2
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Taking Square root of both sides.
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Now taking the positive part,
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Now taking the negative part,
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