Find the nature of the roots of the following quadratic equations:

x² – 4x + 4 = 0

Nature of the quadratic equation can be found out using the following formula

b² – 4ac > 0 for real roots

When we compare the above quadratic equation with the generalized one we get,

ax² + bx + c = 0

a = 1

b = -4

c = 4

⟹ (-4)² – (4 × 1 × 4)

⟹ 16 - 16

⟹ 0

The answer is zero which implies that the quadratic equation has real and equal roots.