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3. Polynomials
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Q2 of 108 Page 40

Solve the following equations by factorization method:

abx2 + (b2 – ac)x – bc = 0


On factorizing the above equation,

abx2 + (b2 – ac)x – bc = 0


abx2 + b2x – acx – bc = 0


bx(ax + b) – c(ax + b) = 0


(bx – c) (ax + b) = 0


Solving the first part,


bx – c = 0


bx = c


x = c/b


Solving the second part,


ax + b = 0


ax = -b


x = -b / a


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Questions · 108
3. Polynomials
1 1 1 1 1 1 2 2 2 2 2 2 3 1 1 1 1 2 2 2 3 3 3 4 1 1 1 1 2 2 2 2 2 2 2 2 2 2 2 1 1 1 1 1 1 1 2 2 2 2 2 2 3 4 5 1 1 1 1 1 1 2 2 2 2 2 2 3 3 3 4 5 1 1 1 1 1 2 3 4 5 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 19 19 19 20 21 21 22 23
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