Q2 of 108 Page 46

The zeroes of the polynomials x2 – x – 6 are:

Solving the quadratic part,

⟹ x2 - x – 6 = 0


⟹ x2 - 3x + 2x – 6 = 0


⟹ x(x - 3) + 2(x - 3) = 0


⟹ (x + 2) (x - 3) = 0


Solving first part,


x + 2 = 0


x = - 2


Solving second part,


x - 3 = 0


x = 3


So the correct answer is C [3, -2].

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