Q12 of 149 Page 16

Write the equation of the tangent to the curve y = x2 – x + 2 at the point where it crosses the y-axis.

Given that the curve y = x2 – x + 2 has a point crosses the y-axis.


The curve will be in the form of (0, y)


⇒ y = 0- 0 + 2


⇒ y = 2


So, the point at which curve crosses the y-axis is (0, 2).


Now, differentiating the equation of curve w.r.t. x



For (0, 2),



Equation of the tangent:



⇒ (y – 2) = -1× (x – 0)


⇒ y – 2 = -x


⇒ x + y = 2


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