The equation of the normal to the curve x = acos3 θ, y = a sin3θ at the point is

Q19 of 149 Page 16

The equation of the normal to the curve x = acos³ θ, y = a sin³θ at the point is

Given that the curve x = acos³ θ, y = a sin³θ have a normal at the point

Differentiating both w.r.t. θ,

For

Slope of the tangent = -1

Equation of normal:

x = y

The slope of the tangent to the curve x = 3t² + 1, y = t³ – 1 at x = 1 is

The curves y = ae^x and y = be^–x cut orthogonally, if

If the curves y = 2 e^x and y = ae^–x interest orthogonally, then a =

The point on the curve y = 6x – x² at which the tangent to the curve is inclined at to the line x + y = 0 is