Find the equation of the tangent and the normal to the following curves at the indicated points:
x = a (θ + sin θ), y = a (1 – cos θ) at θ
finding slope of the tangent by differentiating x and y with respect to theta
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Now dividing
and
to obtain the slope of tangent
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m(tangent) at theta is ![]()
normal is perpendicular to tangent so, m1m2 = – 1
m(normal) at theta is ![]()
equation of tangent is given by y – y1 = m(tangent)(x – x1)
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equation of normal is given by y – y1 = m(normal)(x – x1)
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