Q6 of 149 Page 16

The point on the curve y = x2 – 3x + 2 where tangent is perpendicular to y = x is

Given that the curve y = x2 – 3x + 2 where tangent is perpendicular to y = x


Differentiating both w.r.t. x,



∵ the point lies on the curve and line both


Slope of the tangent = -1


⇒ 2x – 3 = -1


⇒ x = 1


And y = 1-3+2


⇒ y =0


So, the required point is (1, 0).

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