Find the The Slopes of the tangent and the normal to the following curves at the indicated points :
at x = 9
Given:
y =
at x = 9
First, we have to find
of given function, f(x),i.e, to find the derivative of f(x)
⇒ y = ![]()
![]()
⇒ y = (![]()
(xn) = n.xn – 1
The Slope of the tangent is ![]()
⇒ y = (![]()
![]()
![]()
Since, x = 9
x = 9 = ![]()
x = 9 = ![]()
x = 9 = ![]()
x = 9 = ![]()
x = 9 = ![]()
The Slope of the tangent at x = 9 is ![]()
⇒ The Slope of the normal = ![]()
⇒ The Slope of the normal = ![]()
⇒ The Slope of the normal = ![]()
⇒ The Slope of the normal = – 6
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