Q12 of 149 Page 16

Find the equation of a normal to the curve y = x loge x which is parallel to the line
2x – 2y + 3 = 0.

finding the slope of the tangent by differentiating the curve



m(tangent) =


normal is perpendicular to tangent so, m1m2 = – 1


m(normal) =


equation of normal is given by y – y1 = m(normal)(x – x1)


now comparing the slope of normal with the given equation


m(normal) = 1




since this point lies on the curve, we can find y by substituting x



The equation of normal is given by



More from this chapter

All 149 →
10

Find the equation of normal line to the curve y = x3 + 2x + 6 which is parallel to the line x + 14y + 4 = 0.

 11

Determine the equation (s) of tangent (s) line to the curve y = 4x3 – 3x + 5 which are perpendicular to the line 9y + x + 3 = 0.

 13

Find the equation of the tangent line to the curve y = x2 – 2x + 7 which is

parallel to the line 2x – y + 9 = 0

 13

Find the equation of the tangent line to the curve y = x2 – 2x + 7 which is

perpendicular to the line 5y – 15x = 13.