If the straight line xcosα + ysinα = p touches the curve
then prove that
a2cos2α–b2sin2α = ρ2.
Given:
The straight line xcosα + ysinα = p touches the curve
1.
Suppose the straight line xcosα + ysinα = p touches the curve at (x1,y1).
But the equation of tangent to
1 at (x1,y1) is
1
Thus ,equation
1 and xcosα + ysinα = p represent the same line.
∴![]()
⇒ x1
,y1![]()
Since the point (x1,y1) lies on the curve
1
⇒
1
⇒
1
⇒
1
⇒ a2cos2α – b2sin2α = p2
Thus proved.
Couldn't generate an explanation.
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