Find the equation of the tangent and the normal to the following curves at the indicated points:
xy = c2 at (ct, c/t)
finding slope of the tangent by differentiating the curve
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m(tangent) at
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normal is perpendicular to tangent so, m1m2 = – 1
m(normal) at
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equation of tangent is given by y – y1 = m(tangent)(x – x1)
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equation of normal is given by y – y1 = m(normal)(x – x1)
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