Show that the curves
and
interest at right angles
Given:
Curves
+
1 ...(1)
&
+
1 ...(2)
First curve is
+
1
Differentiating above w.r.t x,
⇒
.
= 0
⇒
.![]()
⇒ 
⇒ m1
...(3)
Second curve is
+
1
Differentiating above w.r.t x,
⇒
.
= 0
⇒
.![]()
⇒ 
⇒ m2
...(4)
Now equation (1) – (2) gives
![]()
⇒ x2(
) + y2(
) = 0
⇒ x2(
) = – y2(
)
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ ![]()
⇒ ![]()
⇒
...(5)
When m1
& m2 = ![]()

⇒
×![]()
⇒
×![]()
Substituting
from equation (5),we get
⇒
×![]()
⇒ – 1
∴ The two curves intersect orthogonally,
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.



