Q5 of 149 Page 16

Find the equation of the tangent and the normal to the following curves at the indicated points:

at t = 1/2

finding slope of the tangent by differentiating x and y with respect to t






Now dividing and to obtain the slope of tangent



m(tangent) at t = is


normal is perpendicular to tangent so, m1m2 = – 1


m(normal) at t = is


equation of tangent is given by y – y1 = m(tangent)(x – x1)



equation of normal is given by y – y1 = m(normal)(x – x1)



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