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16. Tangents and Normals
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Q8 of 149 Page 16

The point on the curve y = 12x – x2 where the slope of the tangent is zero will be

Given that the curve y = 12x – x2


The slope of the curve


Given that the slope of the tangent = 0


⇒ 12 – 2x = 0


⇒ x = 6


So, y = 72 – 36


⇒ y = 36


So, the correct option is D.

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The point on the curve y = x2 – 3x + 2 where tangent is perpendicular to y = x is

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Questions · 149
16. Tangents and Normals
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