Let’s find G.C.D of the following algebraic expressions:
4a2b2, 20ab2
4a2b2, 20ab2
Factors of 4a2b2=4×a×a×b×b
Factors of 20ab2=4×5×a×b×b
GCD is the greatest common divisor, which is equal to the product of all the common divisors.
∴ The GCD of 4a2b2, 20ab2 is 4ab2
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