Q3 of 42 Page 136

Let’s find G.C.D of the following algebraic expression:

x3-3x2y, x2-9y2


x3-3x2y=x2(x-3y)


∴Factors of x3-3x2y= x2(x-3y)


x2-9y2=(x + 3y)(x-3y)


∴Factors of x2-9y2=(x + 3y)(x-3y)


GCD is the greatest common divisor, which is equal to the product of all the common divisors.


∴ the GCD of x3-3x2y, x2-9y2 is (x-3y)


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