Q3 of 42 Page 136

Let’s find G.C.D of the following algebraic expression:

x2 + xy,xz + yz, x2 + 2xy + y2


Factors of x2 + xy=x(x + y)

Factors of xz + yz=z(x + y)


Factors of x2 + 2xy + y2=(x + y)2 … (from properties of (a + b)2)


GCD is the greatest common divisor, which is equal to the product of all the common divisors.


∴ the GCD of x2 + xy,xz + yz, x2 + 2xy + y2 is (x + y)


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