Let’s find G.C.D of the following algebraic expressions:
7y3z6, 21y2, 14z2
factors of 7y3z6=7×y×y×y×z×z×z×z×z×z
Factors of 21y2=3×7×y×y
Factors of 14z2=2×7×z×z
GCD is the greatest common divisor, which is equal to the product of all the common divisors.
∴ the GCD of 7y3z6, 21y2, 14z2 is 7
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