Q3 C of 42 Page 136

Let’s find G.C.D of the following algebraic expression:

2ax(a-x)2, 4a2x(a-x)3


Factors of 2ax(a-x)2=2×a×x×(a-x) ×(a-x)


Factors of 4a2x(a-x)3=2×2×a×a×x×(a-x) ×(a-x) ×(a-x)


GCD is the greatest common divisor, which is equal to the product of all the common divisors.


∴the GCD of 2ax(a-x)2, 4a2x(a-x)3 is 2ax(a-x)2


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